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QR Challenge: Swilley Chemistry Moles Review

QuestionAnswer
1. Why is the mole used in Chemistry?to count large numbers of small particles
2. The mole is the SI unit for _____________.amount of matter
3. What is one mole equal to?6.02 x 10^23, 22.4L, grams of a substance
4. One mole of Ca and one mole of O have the same ___________ and different ______.same number of particles and different masses
5. What is the mass of one mole of Mg?24.3050g
6. What is the molar mass of one mole of Mg?24.3050g/mol
7. What is the average atomic mass of Mg?24.3050u
8. What is the mass number of Mg?24.3050
9. What is the molar mass of Al2S3?150.155g/mol
10.How many moles are there in 60.5g of Br?0.757mol Br
11.How many grams are there in 3.56mol of K?139g K
12.How many particles are there in 0.56mol of Fe?3.4x10^23
13.How many moles are there in 4.03x10^23particles of Al?0.669mol Al
14.How many liters are there in 0.289mol of N?6.47L N
15.How many moles are there in 78.4L of O2?3.5mol O2
16.How many grams are there in 8.03x10^23atoms of Rb?114g Rb
17.How many particles are there in 456.4g of Si?9.783x10^24
18.How many liters are there in 1,203.4g of B?2,493.4L B
19.How many particles are in 93.7liters of N2 gas?2.52x10^24
20.What is the percent composition of Mg(OH)2?Mg=41.38%, O=55.17%, H=3.45%
21.What is the percent composition of potassium in KCl?K=52.52%
22.What is the formula that has the smallest whole-number ratio of the elements?empirical formula
23.What is the formula that specifies the actual number of atoms of each element in one molecule or formula unit of the substance?molecular formula
24.The molar mass of nicotine is 162.1 g/mol. It contains 74.0% carbon, 8.7% hydrogen and 17.3% nitrogen. Determine nicotine’s empirical formula and molecular formula.empirical=C5H7N and molecular=C10H14N2
25. Phenyl magnesium bromide is used as a Grignard reagent in organic synthesis. Determine its empirical and molecular formula if its molar mass is 181.313 g/mol and it contains 39.7458% C, 2.77956% H, 13.4050% Mg and 44.0697% Br.empirical and molecular are C6H5MgBr

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