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QR Challenge: stoichiometry

Created using the ClassTools QR Treasure Hunt Generator

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Teacher Notes

A. Prior to the lesson:

1. Arrange students into groups. Each group needs at least ONE person who has a mobile device.

2. If their phone camera doesn't automatically detect and decode QR codes, ask students to

3. Print out the QR codes.

4. Cut them out and place them around your class / school.

B. The lesson:

1. Give each group a clipboard and a piece of paper so they can write down the decoded questions and their answers to them.

2. Explain to the students that the codes are hidden around the school. Each team will get ONE point for each question they correctly decode and copy down onto their sheet, and a further TWO points if they can then provide the correct answer and write this down underneath the question.

3. Away they go! The winner is the first team to return with the most correct answers in the time available. This could be within a lesson, or during a lunchbreak, or even over several days!

C. TIPS / OTHER IDEAS

4. A detailed case study in how to set up a successful QR Scavenger Hunt using this tool can be found here.

Questions / Answers (teacher reference)

Question

Answer

1. what do you need to have before you can answer the question: How many grams of oxygen are need to burn 12.5 g of methane (CH4)?a balanced equation
2. where do you find the coefficients in a balanced equation?in front of the compound or element symbol
3. what do the coefficients represent?moles of each substance
4. given the equation: 3 Pb(NO3)2 + 2 AlCl3 --> 3 PbCl2 + 2 Al(NO3)3 what is the mole ratio between AlCl3 and PbCl2? 2 AlCl3: 3 PbCl2
5. given the equation: 3 Pb(NO3)2 + 2 AlCl3 --> 3 PbCl2 + 2 Al(NO3)3 if you produced 9 moles of PbCl2, how many moles of AlCl3 was required?6 moles AlCl3 (3 times as much as balanced equation)
6. given the equation: 3 Pb(NO3)2 + 2 AlCl3 --> 3 PbCl2 + 2 Al(NO3)3 if you have excess Pb(NO3)2 how much PbCl2 can be produced from 25.0 g of AlCl3?78.2 g PbCl2
7. If instead of having an excess of Pb(No3)2 you had 30.0 g which you mixed with the 25.0 g of AlCl3, how much PbCl2 would be produced? and which reactant would be limiting?19.6 g, PbNO3 would be limiting

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=what-do-you-need-to-have-before-you-can-answer-the-question:--How-many-grams-of-oxygen-are-need-to-burn-12.5-g-of-methane-(CH4)?

Question 1 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=where-do-you-find-the-coefficients-in-a-balanced-equation?

Question 2 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=what-do-the-coefficients-represent?

Question 3 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=given-the-equation:--3-Pb(NO3)2-+-2-AlCl3--->--3-PbCl2-+-2-Al(NO3)3--what-is-the-mole-ratio-between-AlCl3-and-PbCl2?

Question 4 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=given-the-equation:--3-Pb(NO3)2-+-2-AlCl3--->--3-PbCl2-+-2-Al(NO3)3--if-you-produced-9-moles-of-PbCl2,-how-many-moles-of-AlCl3-was-required?

Question 5 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=given-the-equation:--3-Pb(NO3)2-+-2-AlCl3--->--3-PbCl2-+-2-Al(NO3)3-if-you-have-excess-Pb(NO3)2-how-much-PbCl2-can-be-produced-from-25.0-g-of-AlCl3?

Question 6 (of 7)

 


stoichiometry: QR Challenge

https://www.classtools.net/QR/decode.php?text=If-instead-of-having-an-excess-of-Pb(No3)2-you-had-30.0-g-which-you-mixed-with-the-25.0-g-of-AlCl3,-how-much-PbCl2-would-be-produced?-and-which-reactant-would-be-limiting?

Question 7 (of 7)